i,j,s,n:longint;
a:array[0..200] of longint;
begin
readln(n);
a[0]:=1;
for i:=1 to n do
for j:=1 to i do
a[i]:=a[i-j]*a[j-1]+a[i];
end;
writeln(a[n]);
end.
快速帮助 | 运行状态 | 反馈举报 | 关于我们 | 免责声明 | 浙ICP备11060257号 Processed in 0.0034 Second(s) Copyright (C) RQNOJ 2007-2019. All Rights Reserved.