int main()
{
int n,m,k,x,e=10,ans=1;
scanf("%d %d %d %d",&n,&m,&k,&x);
while(k>0)
if(k%2==1) ans=e*ans%n;
k/=2;
e=e*e%n;
}
printf("%d",((m*ans)%n+x)%n);
快速帮助 | 运行状态 | 反馈举报 | 关于我们 | 免责声明 | 浙ICP备11060257号 Processed in 0.0036 Second(s) Copyright (C) RQNOJ 2007-2019. All Rights Reserved.