讨论 / 求助 大部分过不去啊- =
Nostalk 2012-12-22 05:33:00
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const mdx:array[1..8]of longint=(1,-1,2,-2,1,-1,2,-2);

mdy:array[1..8]of longint=(2,-2,1,-1,-2,2,-1,1);

zdx:array[1..2]of longint=(1,0);

zdy:array[1..2]of longint=(0,1);

var m,n,k,l,ans:longint; x1,y1,x2,y2:longint;

i,j:longint;

a:array[0..10000000,0..10000000]of qword;

f:array[0..10000,0..10000]of boolean;

procedure dfs(x,y:longint);

var i,j:longint;

begin

if (x=x1)and(y=y1) then begin

inc(ans);

exit;

end;

for i:=1 to 2 do

begin

if (x+zdx[i]>=0)and(x+zdx[i]<=x1) then

if (y+zdy[i]>=0)and(y+zdy[i]<=y1) then

if (f[x+zdx[i],y+zdy[i]]=false) then

begin

f[x+zdx[i],y+zdy[i]]:=true;

dfs(x+zdx[i],y+zdy[i]);

f[x+zdx[i],y+zdy[i]]:=false;

end;

end;

end;

begin

read(x1,y1,x2,y2);

for i:=1 to 8 do

begin

f[x2+mdx[i],y2+mdy[i]]:=true;

f[x2,y2]:=true;

end;

dfs(0,0);

write(ans);

end.

#1 性徐的人@2012-12-22 03:01:00
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我来刷个分

哪过不去,哪道?

#2 性徐的人@2012-12-22 03:01:00
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a

b

#3 Nostalk@2012-12-22 05:33:00
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Yoooooo!!~

不要DP的 能过大部分点的DFS就行 求修改

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