任昊 2013-10-28 22:02:00
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var a:array[1..1000]of integer;
a1:array[1..100]of integer;
n,i,s:integer;
begin
read(n);
for i:=1 to n do
read(a1[i]);
for i:=1 to 1000 do
a[i]:=0;
for i:=1 to n do
a[a1[i]]:=1;
for i:=1 to 1000 do
if a[i]=1
then inc(s);
writeln(s);
for i:=1 to 1000 do
if a[i]=1
then
write(i,' ');
end.
#2 lemontree712@2013-11-08 20:03:48
32329
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#include <stdio.h>
#include <iostream>
using namespace std;
int main (){
freopen ("rp爆发.out","w",stdout);
long long rp=100000000000;
while (1){
rp+=100000000000;
}
printf ("%lld",rp);
return 0;
}
运行结果：rp爆满以至于溢出
祝2小时后，我们都能在NOIP中创造佳绩！！！人品++！
#3 lemontree712@2013-11-08 20:05:08
32330
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#include"stdio.h"
#include"iostream"
using namespace std;
int main (){
freopen ("rp爆发.out","w",stdout);
long long rp=100000000000;
while (1){ rp+=100000000000; }
printf ("%lld",rp);
return 0; }
运行结果：rp爆满以至于溢出 ！
祝2小时后，我们都能在NOIP中创造佳绩！！！人品++！